Hess’s Law and Heats of Formation

professor Dave here ,I want to tell you
about Hess’s law thermochemical equations can be manipulated to give
important data about chemical reactions. we can use them to predict exactly how
much energy will be absorbed or released by a reaction, which is very important
because we don’t want any unexpected explosions. there are two ways we can use
tabulated thermochemical data to calculate the Delta H of any reaction.
the first way requires that we manipulate thermochemical equations in
specific ways, so let’s be aware of some rules. first if the reaction has a
particular Delta H, the reverse of the reaction will have
the opposite Delta H, or the same number with reversed sign. second, if molar
quantities in the equation are multiplied by a coefficient, so is the
Delta H. so if you double all the substances, double the Delta H. these are things we can do to
thermochemical data to be able to add equations together to result in a
reaction we are curious about. here’s what I mean. let’s say we want to
know about the change in enthalpy associated with a reaction like this one,
but it is difficult to measure experimentally. we can take other
reactions with known enthalpy changes and rearrange them to align with our
equation and get the data we want. the first reaction provided has carbon
graphite on the left, which is where we want it, but the equation we want has two
moles of graphite, so let’s double this one, we get two moles of everything
instead of one, and we double the Delta H. next, this other one has CO on the right
where we want it, and in the right amount so all we need to do is add these
equations together. the O2 and CO2 will cancel because they are present in the
same amount on both sides, and we are left with the substances in our original
equation. since we added the equations we also add
the Delta H’s to get the Delta H for our equation. this kind of manipulation
is allowed by Hess’s law. we can manipulate the coefficients of a
reaction or reverse its direction in any way necessary as long as we change
the Delta H associated with it in the appropriate way. then we add or subtract
the equations as necessary to give us precisely the equation in question. the
Delta H you get by doing the arithmetic will be the Delta H for the reaction.
another way to calculate an unknown Delta H is to use standard enthalpies of
formation. this is denoted by the following symbol and it represents the
enthalpy associated with forming one mole of a substance from its respective
elements in their standard and most stable state. most stable state means the
most common allotrope, or physical form of an element. so carbon graphite instead
of diamond, diatomic oxygen instead of ozone and so forth. standard state just refers to standard
temperature and pressure which is room temperature and atmospheric pressure at
sea level, that’s what is meant by the degree symbol. we can calculate the
change in enthalpy for a reaction by adding up the standard heats of
formation of the products and then subtracting the sum of the standard
heats of formation of the reactants. the heats of formation can be found in your
textbook or online, and you just plug them in, multiplying each value by the
coefficients in the balanced equation. let’s check comprehension thanks for watching guys subscribe to my
channel for more tutorials and as always feel free to email me
thank you professor
Thank you so much 🙂 I can't believe that you only have a few subscribers even though you can explain the chemistry concepts in such a way that is comprehensible to the viewers (even those who are not adept at chemistry). Cheers! 🙂
you must denote the state of the substance in the equation especially for water
cuz the standard enthalpy formation are differ if it is gas liquid or solid
Informative , and helpful.
im sorry, im still having a hard time
In the first example 2CO2 -> 2CO + O2 the Delta H si positive, not negative because the opposite reaction is exothermic. So the result of the calculation is incorrect.
help full
still having hard time i understood the concept but when chemical reaction is given am blank please help
thanks a lot helped clear some confusion
Thank you sir helped me revised… Would definetly mail for any doubts
Saved me for my exams… Thank you professor
4.12 the tune sounds like Hotline Bling's
making 1 CO from 1 C generates 676,5kJ
making 1 CO2 from 1 C generates just 393,5kJ
how does this fit together?
Thank you Professor Dave
Sweet Jesus thankyou
thank u pro, this is very helpfull
that would have been more helpful if I wasn't so distracted by your mesmerizing chest hair poking through <3<3<3
I saw somewhere that we cannot measure enthalpy of formation of methane directly but i can't tell why… can u plz explain that why we can't measure enthalpy of formation of methane directly?
One has to specify whether one is using the heat of formation for H2O; either (g) or (l), they are different.
Why the second equation was not doubled?
you help me more than my professors sometimes thank you
THANK YOU JESUS
thank you Jesus
Thanks
Thanks a lot sir
Ooooooohh nice.
thank you .
Great video! Super clear and precise with no wasted time. Much more efficient and easier to keep engaged than those videos that write everything out. Thanks
Thank you thank you thank you! Heroooeeee
Best
should state what state they are in (l), (g), (aq) or (s)…..for instance, NH3 are you talking about the (g) or (aq). Im assuming gas only because of the value you have chosen.
Thanx
thank you
You deserve to have more subscribers. Thank you for all the clear explanations. 💯✔
You rock Dave!
Many thanks 🙂
I like it that the comprehension doesn't give any information and we have to find it ourself.
Very good teacher. You're saving my butt
Thanks for the tutorial. In order to reach the formation enthalpy for 1 mol of products, what should I do? Thanks!
Sir, Why heat of Formation of organic compounds are not measured directly?
I'm indian…we have grabbed this concept when we were 15….
thank you for your videos. I find it's really useful
Thank you sir ! Lots of love from India❤!!
Prof. Dave is college Jesus…. he makes me understand things I never thought I would be able to understand. Prof. Dave is the G.O.A.T of helping average people ty Prof 🙂
Thx bruh.
Good work!
You teach everything perfectly in just 5 to 10 minutes….👍
thanks sir
thanks sir
👍👍👍
Sorry guys, there's an error! At 1:26, the second reaction with carbon dioxide as a reactant should have a change in enthalpy of positive 566 kJ. That changes the answer from what I've shown so please make a note of it. Luckily this error doesn't change the algorithm used, so apart from that you can still apply this concept to any set of reactions as shown here!
Make a video on Cp Cv and gamma. It's a lot confusing.
Sir how to get the delta h of the equation?
How do the O2 cancel put at 2:24, one equation has 4 the other has 2…? (i.e 2O2 and the other is just O2?)
No offense but the beginning really made me lmao
U have made this topic very easy in just about 5 min
Super work👍👍👍👍
Gotta love the comprehension music
You saved my finals
Thanks you, Prof.Dave
Thank you Dave, very cool!
You explained in 45 seconds perfectly what I have struggled for days to understand. I bow my hat to you, my good sir.
Super sir great job
I don't understand, in the equations there is an unequal amount of oxygen, so why do we remove it still?
Professor Dave looks like a real Greek Science Nerd. Thanks Professor Dave 🙂
Dear Prof Dave, your podcasts including this one on Hess' Law are great. You have explained the chemical reactions so well. You are great and thanks for making Chemistry a lot more easier. Continue to do the great works with your podcasts.
This 4 min video is much better than the 1and a half hour lecture my professor gave me
Thx man… Love your vids….
I should have came here earlier! :' ) sobs
Prof. Your video is very helpful even if it some is an unknown topic for me but when you explain it is understandable.
Thank you professor dave 👍
for the comprehension question, dont we need the states of matter?
For last part , why we have Heat of reactanct minus Heat of products ? .In hess law it is opposite version. Thansk
Thanks
Thank you professor dave you are a blessing to all students and learners 🙏
This channel is great! I get frustrated when I have to watch a 10-30 minute video just to explain a specific concept when you can just explain in it in less than 5! Really appreciate it